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The idle-cycle time and the machine-s etup time must be added to the milling time calculated according to (2 ) . The idle-cycle time is determined from the technical data of the machine. For the S - 4 0 machine the idle T m . Having calculated the machine-cycle tim e Tmach= T m + T i for machin- ing one part, it is compared with the technical data of the machine, and the camshaft speed closest to that which would give one camshaft rotation during mach is s elected. The calculated cutting speed is also compared with the machine capabilities and the closest available fo rm - cutter spindle speed is s elected. The method of calculation of the cutting c onditions and the ma chine production rate will be illus trated in the following example . It is required to mill the teeth of a third-wheel pinion of module 0.103 mm, z = 8 . The length of cut is I = 0.80 mm, the material U7A V steel. The data necessary for the calculation are first written down. The feed per tooth of the form cutter is Sz = 0 .0034 mm (Table 8). The cutting speed is fl = 50.3 m/min (Table 9). The form-cutter dimensions are taken from Table 4 : diameter 8 mm, 1 6 cutter teeth. The cutter-spindle speed chosen is n = 2000 rpm. The length of cut is, from the drawing, I = 0.8 mm. The cutter approach is /1 = 1 .5 mm (Appendix 3), The overtravel is selected as /2 = 1 .2 mm. The total travel is therefore L = 3.5 mm. The time required for milling the pinion in one pass is according to (2) T. = m 3.5 · 8 . = 0'25 mm. The idle movements taking, according to the machine data, 7 o/o of the milling time, we have 0.25 .7 0 2 . Ti = IOO _ 1 = .0 mm. The machine-cycle time required for machining the pinion in one pass will therefore be Tmach = T m + T i = 0.25 + 0.02 � 0.27 min. If two passes are to be made, we must add the time taken by the form-cutter shifting which requires one camshaft revolution. At naux = 20 rpm this takes 1/20 = 0.05 min. The piece time, T p• for one cycle of the S-40 machine will therefore be T 0 = Tm + T i + Taux = 0.25 + 0.02 + 0.05 = 0.32 min. For two passes, this time is doubled, and is 0 .64 min. The calculated production rate of the machine will be A = ..i§.Q. = 750 pieces per working shift. The data obtained are then compared with the machine dat g :64 The camshaft speeds available are n = 9, 19.2 or 3 0 rpm ; the time per camshaft revolution will accord ingly be : 0.11, 0.052 , or 0.033 min. The calculated time T mach required for milling one tooth is 0.27/8 = = 0.034 min. According to the specifications of the machine, the value closest to this is 0.033 min, corresponding to n= 30 rpm. 480 The actual machine production rate will therefore be A = 2 ( 0.0033 .8 + 0.05) = 764 pieces per shift. 1 8 1 |